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1z0-071 Practice Questions

Question # 1

View the Exhibit and examine the structure of the PRODUCTS table. (Choose the best
answer.)

You must display the category with the maximum number of items.
You issue this query:
SQL > SELECT COUNT(*), prod_category_id
FROM products
GROUP BY prod_category_id
HAVING COUNT(*) = (SELECT MAX(COUNT(*)) FROM porducts);
What is the result?
You must display the category with the maximum number of items.
You issue this query:
SQL > SELECT COUNT(*), prod_category_id
FROM products
GROUP BY prod_category_id
HAVING COUNT(*) = (SELECT MAX(COUNT(*)) FROM porducts);
What is the result?

A.

It generates an error because = is not valid and should be replaced by the IN operator.

B.

It executes successfully but does not give the correct output.

C.

It executes successfully and gives the correct output.

D.

It generate an error because the subquery does not have a GROUP BY clause.



D.

It generate an error because the subquery does not have a GROUP BY clause.




Question # 2

You notice a performance change in your production Oracle 12c database. You want to
know which change caused this performance difference.
Which method or feature should you use?

A.

Compare Period ADDM report.

B.

AWR Compare Period report.

C.

Active Session History (ASH) report.

D.

Taking a new snapshot and comparing it with a preserved snapshot.



B.

AWR Compare Period report.




Question # 3

View the exhibit and examine the structures of the EMPLOYEES and DEPARTMENTS
tables.
EMPLOYEES
NameNull?Type
----------- -------
EMPLOYEE_IDNOT NULLNUMBER(6)
FIRST_NAMEVARCHAR2(20)
LAST_NAMENOT NULLVARCHAR2(25)
HIRE_DATENOT NULLDATE
JOB_IDNOT NULLVARCHAR2(10)
SALARYNUMBER(10,2)
COMMISSIONNUMBER(6,2)
MANAGER_IDNUMBER(6)
DEPARTMENT_IDNUMBER(4)
DEPARTMENTS
NameNull?Type
----------- -------
DEPARTMENT_IDNOT NULLNUMBER(4)
DEPARTMENT_NAMENOT NULLVARCHAR2(30)
MANAGER_IDNUMBER(6)
LOCATION_IDNUMBER(4)
You want to update EMPLOYEES table as follows:
You issue the following command:
SQL> UPDATE employees
SET department_id =
(SELECT department_id
FROM departments
WHERE location_id = 2100),
(salary, commission) =
(SELECT 1.1*AVG(salary), 1.5*AVG(commission)
FROM employees, departments
WHERE departments.location_id IN(2900, 2700, 2100))
WHERE department_id IN
(SELECT department_id
FROM departments
WHERE location_id = 2900
OR location_id = 2700;
What is outcome?

A.

It generates an error because multiple columns (SALARY, COMMISSION) cannot be
specified together in an UPDATE statement.

B.

It generates an error because a subquery cannot have a join condition in a UPDATE
statement.

C.

It executes successfully and gives the desired update

D.

It executes successfully but does not give the desired update



D.

It executes successfully but does not give the desired update




Question # 4

Which two statements are true about Data Manipulation Language (DML) statements?

A.

An INSERT INTO...VALUES.. statement can add multiple rows per execution to a table.

B.

An UPDATE... SET... statement can modify multiple rows based on multiple conditions
on a table.

C.

A DELETE FROM..... statement can remove rows based on only a single condition on a
table.

D.

An INSERT INTO... VALUES..... statement can add a single row based on multiple
conditions on a table.

E.

A DELETE FROM..... statement can remove multiple rows based on multiple conditions on a table.



B.

An UPDATE... SET... statement can modify multiple rows based on multiple conditions
on a table.


E.

A DELETE FROM..... statement can remove multiple rows based on multiple conditions on a table.


References:
http://www.techonthenet.com/sql/and_or.php



Question # 5

In the PROMOTIONS table, the PROMO_BEGIN_DATE column is of data type DATE and the default date format is DD-MON-RR.Which two statements are true about expressions using  PROMO_BEGIN_DATE contained a query?

A.

PROMO_BEGIN_DATE – 5 will return a date.

B.

PROMO_BEGIN_DATE – SYSDATE will return a number.

C.

TO_NUMBER(PROMO_BEGIN_DATE) – 5 will return a number.

D.

TO_DATE(PROMO_BEGIN_DATE * 5) will return a date.

E.

PROMO_BEGIN_DATE – SYSDATE will return an error.



A.

PROMO_BEGIN_DATE – 5 will return a date.


B.

PROMO_BEGIN_DATE – SYSDATE will return a number.




Question # 6

Which two statements are true regarding multiple-row subqueries? (Choose two.)

A.

They can contain group functions.

B.

always contain a subquery within a subquery.

C.

They use the < ALL operator to imply less than the maximum.

D.

They can be used to retrieve multiple rows from a single table only.

E.

 They should not be used with the NOT IN operator in the main query if NULL is likely to
be a part of the result of the subquery.



A.

They can contain group functions.


E.

 They should not be used with the NOT IN operator in the main query if NULL is likely to
be a part of the result of the subquery.




Question # 7

The ORDERS table a primary key constrain on the ORDER_ID column. The ORDER_ITEMS table has a foreign key constraint on the ORDER_ID column, referencing the primary
key of the ORDERS table.
The constraint is defined with ON DELETE CASCADS.
There are rows in the ORDERS table with an ORDER_TOTAL of less than 1000.
Which three DELETE statements execute successfully?

A.

DELETE * FROM orders WHERE order_total < 1000;

B.

DELETE FROM orders;

C.

DELETE order_id FROM orders WHERE order_total < 1000;

D.

DELETE orders WHERE order_total < 1000;

E.

DELETE FROM orders WHERE order_total < 1000;



B.

DELETE FROM orders;


D.

DELETE orders WHERE order_total < 1000;


E.

DELETE FROM orders WHERE order_total < 1000;




Question # 8

Evaluate these commands which execute successfully:

Which two statements are true about the ORD_ITEMS table and the ORD_SEQ sequence?

A.

Sequence ORD_SEQ cycles back to 1 after every 5000 numbers and can cycle 20 times.

B.

Any user inserting rows into table ORD_ITEMS must have been granted access to sequence ORD_SEQ.

C.

Column ORD_NO gets the next number from sequence ORD_SEQ whenever a row is inserted into
ORD_ITEMS and no explicit value is given for ORD_NO.

D.

If sequence ORD_SEQ is dropped then the default value for column ORD_NO will be NULL for rows
inserted into ORD_ITEMS.

E.

Sequence ORD_SEQ is guaranteed not to generate duplicate numbers.



B.

Any user inserting rows into table ORD_ITEMS must have been granted access to sequence ORD_SEQ.


E.

Sequence ORD_SEQ is guaranteed not to generate duplicate numbers.




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Oracle 1z0-071 Exam Dumps

Exam Name: Oracle Database 12c SQL
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  • Total Questions: 326
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